/* See LICENSE file for copyright and license details. */ #include "stream.h" #include "util.h" #include #include #include #include USAGE("luma-stream") static void process_xyza(struct stream *colour, struct stream *luma, size_t n) { size_t i; double a, y; for (i = 0; i < n; i += colour->pixel_size) { a = ((double *)(luma->buf + i))[1]; a *= ((double *)(luma->buf + i))[3]; y = ((double *)(colour->buf + i))[1]; ((double *)(colour->buf + i))[0] += y * a - y; ((double *)(colour->buf + i))[1] = y * a; ((double *)(colour->buf + i))[2] += y * a - y; /* * Note, this changes the luma only, not the saturation, * so the result may look a bit weird. To change both * you can use `blind-arithm mul`. * * Explaination of algorithm: * * Y is the luma, but (X, Z) is not the chroma, * but in CIELAB, L* is the luma and (a*, *b) is * the chroma. Multiplying * * ⎛0 1 0⎞ * ⎜1 −1 0⎟ * ⎝0 1 −1⎠ * * (X Y Z)' gives a colour model similar to * CIE L*a*b*: a model where each parameter is * a linear transformation of the corresponding * parameter in CIE L*a*b*. The inverse of that * matrix is * * ⎛1 1 0⎞ * ⎜1 0 0⎟ * ⎝0 0 −1⎠ * * and * * ⎛1 1 0⎞⎛a 0 0⎞⎛0 1 0⎞ ⎛1 a−1 0⎞ * ⎜1 0 0⎟⎜0 1 0⎟⎜1 −1 0⎟ = ⎜0 a 0⎟. * ⎝0 0 −1⎠⎝0 0 1⎠⎝0 1 −1⎠ ⎝0 a−1 1⎠ * * Explanation of why changing only the luma looks weird: * * Consider when you are workings with colours, * when you want to change the brightness of a * colour, you multiply all parameters: red, green, * and blue, with the same value (this is however * only an approximation in most cases, since you * are usually usally working with colours that * have the sRGB transfer function applied to their * parameters). This action is the same in all * colour models and colour spaces that are a * linear transformation of the sRGB colour spaces * (sans transfer function); this is simply because * of the properties of linear transformations. * * The reason you change brightness this way can * be explained by how objects reflect colour. * Objects can only reject colours that are present * in the light source. A ideal white object will look * pure red if the light sources is ideal red, and a * a ideal blue object will pure black in the same * light source. An object can also not reflect * colours brighter than the source. When the brightness * of a light source is changed, the intensity of all * colours (by wavelength) it emits is multiplied by * one value. Therefore, when changing the brightness * it looks most natural when all primaries (red, green, * and blue) are multiplied by one value, or all * parameters of the used colour spaces is a linear * transformation of sRGB, such as CIE XYZ. */ } } int main(int argc, char *argv[]) { struct stream colour, luma; void (*process)(struct stream *colour, struct stream *luma, size_t n); UNOFLAGS(argc != 1); eopen_stream(&colour, NULL); eopen_stream(&luma, argv[0]); if (!strcmp(colour.pixfmt, "xyza")) process = process_xyza; else eprintf("pixel format %s is not supported, try xyza\n", colour.pixfmt); fprint_stream_head(stdout, &colour); efflush(stdout, ""); process_two_streams(&colour, &luma, STDOUT_FILENO, "", process); return 0; }