/**
* Copyright © 2014 Mattias Andrée (m@maandree.se)
*
* This program is free software: you can redistribute it and/or modify
* it under the terms of the GNU Affero General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* This program is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU Affero General Public License for more details.
*
* You should have received a copy of the GNU Affero General Public License
* along with this program. If not, see .
*/
package algorithms.bits;
/**
* Compute the minimum or maximum of two integers
*/
public class MinMax
{
£S=${T_S#*_}
/**
* Compute the minimum of two integers
*
* @param a One of the integers
* @param b The other of the integers
* @return The minimum of the two integers
*/
public static £{T} min(£{T} a, £{T} b)
{
return (£{T})(b ^ (£{T})((a ^ b) & ((a - b) >> £{S})));
/* In C you can also do:
* b ^ ((a ^ b) & -(a < b))
*/
/*
* Other version that can be faster:
* (a < b) ? a : b
* Assuming you now that INT_MIN <= x - y <= INT_MAX:
* b + ((a - b) & ((a - b) >> (sizeof(£{T}) * CHAR_BITS - 1)))
*/
}
/**
* Compute the maximum of two integers
*
* @param a One of the integers
* @param b The other of the integers
* @return The maximum of the two integers
*/
public static £{T} max(£{T} a, £{T} b)
{
return (£{T})(a ^ (£{T})((a ^ b) & ((a - b) >> £{S})));
/* In C you can also do:
* a ^ ((a ^ b) & -(a < b))
*/
/*
* Other version that can be faster:
* (a < b) ? b : a
* Assuming you now that INT_MIN <= x - y <= INT_MAX:
* a - ((a - b) & ((a - b) >> (sizeof(£{T}) * CHAR_BITS - 1)))
*/
}
£>done
}