/** * Copyright © 2014 Mattias Andrée (m@maandree.se) * * This program is free software: you can redistribute it and/or modify * it under the terms of the GNU Affero General Public License as published by * the Free Software Foundation, either version 3 of the License, or * (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU Affero General Public License for more details. * * You should have received a copy of the GNU Affero General Public License * along with this program. If not, see . */ package algorithms.bits; /** * Compute the minimum or maximum of two integers */ public class MinMax { £S=${T_S#*_} /** * Compute the minimum of two integers * * @param a One of the integers * @param b The other of the integers * @return The minimum of the two integers */ public static £{T} min(£{T} a, £{T} b) { return (£{T})(b ^ (£{T})((a ^ b) & ((a - b) >> £{S}))); /* In C you can also do: * b ^ ((a ^ b) & -(a < b)) */ /* * Other version that can be faster: * (a < b) ? a : b * Assuming you now that INT_MIN <= x - y <= INT_MAX: * b + ((a - b) & ((a - b) >> (sizeof(£{T}) * CHAR_BITS - 1))) */ } /** * Compute the maximum of two integers * * @param a One of the integers * @param b The other of the integers * @return The maximum of the two integers */ public static £{T} max(£{T} a, £{T} b) { return (£{T})(a ^ (£{T})((a ^ b) & ((a - b) >> £{S}))); /* In C you can also do: * a ^ ((a ^ b) & -(a < b)) */ /* * Other version that can be faster: * (a < b) ? b : a * Assuming you now that INT_MIN <= x - y <= INT_MAX: * a - ((a - b) & ((a - b) >> (sizeof(£{T}) * CHAR_BITS - 1))) */ } £>done }