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authorMattias Andrée <maandree@operamail.com>2014-01-20 00:17:53 +0100
committerMattias Andrée <maandree@operamail.com>2014-01-20 00:17:53 +0100
commitde6791a184f397bb75ccf3d3ebee213f3b959a6d (patch)
treee67b936b0b31fa390da26b85c032c594cac3f5eb /src/algorithms/arrays
parentadd legal files (diff)
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add MinMax
Signed-off-by: Mattias Andrée <maandree@operamail.com>
Diffstat (limited to '')
-rw-r--r--src/algorithms/arrays/MinMax.java49
1 files changed, 49 insertions, 0 deletions
diff --git a/src/algorithms/arrays/MinMax.java b/src/algorithms/arrays/MinMax.java
new file mode 100644
index 0000000..ccdbc56
--- /dev/null
+++ b/src/algorithms/arrays/MinMax.java
@@ -0,0 +1,49 @@
+/**
+ * Copyright © 2014 Mattias Andrée (maandree@member.fsf.org)
+ *
+ * This program is free software: you can redistribute it and/or modify
+ * it under the terms of the GNU Affero General Public License as published by
+ * the Free Software Foundation, either version 3 of the License, or
+ * (at your option) any later version.
+ *
+ * This program is distributed in the hope that it will be useful,
+ * but WITHOUT ANY WARRANTY; without even the implied warranty of
+ * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
+ * GNU Affero General Public License for more details.
+ *
+ * You should have received a copy of the GNU Affero General Public License
+ * along with this program. If not, see <http://www.gnu.org/licenses/>.
+ */
+package algorithms.arrays;
+
+
+/**
+ * Class for finding the minimum and maximum values in one iteration
+ */
+public class MinMax
+{
+£>for T in boolean char byte short int long float double T T+; do . src/comparable
+ /**
+ * Find the minimum and maximum values in an array
+ *
+ * @param items The items over to search
+ * @return An array with two elements, at index 0, the minimum value, and at position 1, the maximum value
+ */
+£>[ $T = T ] &&
+ @SuppressWarnings("unchecked")
+ public static £(fun "${T}[]" getBounds "${T}[] items")
+ {
+ £{T} max, min, cur;
+ max = min = items[0];
+
+ for (int i = 1, n = items.length; i < n; i++)
+ if (£(greater "cur = items[i]" "max"))
+ max = cur;
+ else if (£(less "cur" "min"))
+ min = cur;
+
+ return £(T-array min max);
+ }
+£>done
+}
+